ls1 = [1, 2, 3, 2]

ls2 = ["aa", "bb", "cc", "dd", "ee"]

d = {}

for index in range(len(ls1)):

    d[ls1[index]] = ls2[index]

print(d)

a = [1, 2, 3]

for i in a[::-1]:

    print(i, end=",")

s = ["seashell", "gold", "pink", "brown", "purple", "tomato"]

print(s[1:4:2])

s = list(

    "巴老爷有八十八棵芭蕉树，来了八十八个把式要在巴老爷八十八棵芭蕉树下住。老爷拔了八十八棵芭蕉树，不让八十八个把式在八十八棵芭蕉树下住。八十八个把式烧了八十八棵芭蕉树，巴老爷在八十八棵树边哭。"

)

以下选项中能输出字符“八”第一次出现的索引位置的是

ls1 = [1, 2, 3, 4, 5]

ls2 = ls1

ls2.reverse()

print(ls1)

ls = []

for m in "想念":

    for n in "家人":

        ls.append(m + n)

print(ls)

a = input("").split(",")

if isinstance(a, list):

    print("{} is list".format(a))

else:

    print("{} is not list".format(a))

代码执行时，从键盘获得1，2，3，则代码的输出结果是

ls = ["浣熊", "豪猪", "艾草松鸡", "棉尾兔", "叉角羚"]

x = "豪猪"

print(ls.index(x, 0))

a = input("").split(",")

x = 0

while x < len(a):

    print(a[x], end="")

    x += 1

代码执行时，从键盘获得a,b,c,d，则代码的输出结果是

letter = ["A", "B", "C", "D", "D", "D"]

for i in letter:

    if i == "D":

        letter.remove(i)

print(letter)

L1 = [4, 5, 6, 8].reverse()

print(L1)

sites = ["BIT", "NJN", "NJNU", "HYIT"]

for site in sites:

    if site == "NJN":

        print("南京大学")

        break

    print("循环数据" + site)

else:

    print("没有循环数据!")

    print("完成循环!")

ls = [[1, 2, 3], "python", [[4, 5, "ABC"], 6], [7, 8]]

print(ls[2][1])

ls = [12, 44, 23, 46]

for i in ls:

    if i == "44":

        print("found it! i=", i)

        break

else:

    print("not found it...")

list1 = [1, 2, 3]

list2 = [4, 5, 6]

print(list1 + list2)

a = [1, 2, 3]

b = a[:]

print(b)