ls=[256, "Byte",512,"bit"] lt=ls

ls[1]="Python"

print(1t)输出的结果是

ls=list({"a",“b", "Python","c","d})

for e in ls:

print(e,"end="")

print函数输出的结果

dic = [90:'Aele',87:'Bob’ 93:'lala’}

 print(dic.pop(90,-1),len(dic))

dd={‘a' :90,'b’:87,'c':93}

print(max(dd),min(dd))

ls = [“2020”,“20.20”,"Python"]

  ls.append(2020)

1s.append([2020,“2020])

  print(ls)

s =[4,2,9,1]

s.insert(2,3)

print(s)

L1=[1,2, 3,4]

L2=L1.copy()

L2.reverse ()

print(L1)

#列表对象的赋值和拷贝函数操作的差别，后者是给第二个对象复制了一份新的变量;因此修改了1s2的内容，则1s1并没有改变

tb={ yingyu’:20,'shuxue’:30,'yuwen':40}

stb={}

for it in tb.items():

   print(it)

   ————

   print(stb)

dd ={'chinese':200,'pe':187,'Gana':930} 

print(dd.keys())

print(1s[2][-2][1:-1:2])

print函数输出的结果

d=｛' 1' :1,' 2':2,"3':3,'4':4}

d2=d

d['2']=5

print(d['2']+d2['2'])

1s=[2,5,7,1,6]

1t=sorted(ls,reverse=True)

print(ls,lt)

print函数输出的结果是

1s=1ist(range(5))

1t=[['a',b'],"c"]

1s=[-1:1:-2]=1t

print(ls)

print函数输出的结果

nums=[1, 2, 3, 4]

nums.append([5, 6,7,8])

print(len (nums))