not x or y 的运算结果为()

not xor not y and z的运算结果()

not xor y or not y and x的运算结果为()

dict ={}

date=['2021-08-11'2021-09-212021-08-28]

temp =['18','29','31']

for i in range(3):

dict['date’]= date[i]dict['weather']= temp[i]list.append(dict)

执行上面代码后，list的值为

[{'date': '2021-08-11', 'weather': '18'}, {'date’: '2021-09-21', 'weather': '29'}, {'date': '2021-08-28','weather': '31'}